# Question #e1c1e

May 19, 2017

M (-10, -3.6)

#### Explanation:

The point M (10, 0) is located on the horizontal axis Ox.
After rotation of ${200}^{\circ}$ about the origin O, the terminal side OM will be in Quadrant 3, and will make with the Ox axis an angle t that equals to:
$t = 200 - 180 = {20}^{\circ}$
The coordinates of the new point M are: -10 and y -->
$\tan 20 = 0.36 = \frac{y}{-} 10$
$y = \left(- 10\right) \left(0.36\right) = - 3.6$

Coordinates of the new point M (-10, -3.6)