Simplify #4(tan^2x-sec^2x)#?

1 Answer
Narad T. · Shwetank Mauria
May 22, 2017

The answer is #-4#

Explanation:

We need

#cos^2x+sin^2x=1#

#tanx=sinx/cosx#

#secx=1/cosx#

Therefore,

#4(tan^2x-sec^2x)=4(sin^2x/cos^2x-1/cos^2x)#

#=4((sin^2x-1))/cos^2x#

#=-4((1-sin^2x))/cos^2x#

#=-4cancel(cos^2x)/cancel(cos^2x)#

#=-4#

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