Question #24dc0

1 Answer
May 22, 2017

#210#

Explanation:

#"using the definition of " ""^nC""_r#

#• ""^nC""_r=(n!)/(r!(n-r)!)#

#"where " n! =n(n-1)(n-2)(n-3)..... xx1#

#rArr""^(10)C""_4=(10!)/(4!xx6!)larr" 6! cancel"#

#color(white)(xxxxxx)=(10xx9xx8xx7)/(4xx3xx2xx1)#

#color(white)(xxxxxx)=210#