How do you name...#H_3C-C(=O)CH_2CH(CH_3)CH_2CH_2CH_3#?

1 Answer
anor277
May 23, 2017

#H_3stackrel1C-stackrel2C(=O)stackrel3CH_2stackrel4CH(CH_3)stackrel5CH_2stackrel6CH_2stackrel7CH_3#.

Explanation:

Drawing it out would lead you to realize that the LONGEST chain is in fact 7 carbons long as shown; and thus this is an heptanone.

The carbonyl takes priority, and is thus #stackrel2C#. #stackrel(4)C# is substituted by a methyl group, and is thus (in principle at least) an asymmetric centre.

You still have to name the structure............good luck.

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