# Question #a903c

May 26, 2017

$N a O H + H N {O}_{3} \to {H}_{2} O + N a N {O}_{3}$

#### Explanation:

This is a double displacement reaction.

This means the cations will be switched around (or the anions if you prefer).

This means the Na+ ion is switched with the H+ ion.

The final answer will then be $N a O H + H N {O}_{3} \to {H}_{2} O + N a N {O}_{3}$

May 26, 2017

$\text{NaNO"_3 + "H"_2"O}$

#### Explanation:

This is an example of a neutralization reaction, which is a subset of double displacement reactions.

A neutralization reaction is when an acid and a base react to form water and salt.

Taking the example problem,

$\textcolor{w h i t e}{- - - -} N a O H + H N {O}_{3} \to N a N {O}_{3} + {H}_{2} O$

$\text{NaOH}$ (a strong base) and ${\text{HNO}}_{3}$ (a strong acid) react in a 1:1 mole ratio, where 1 mole of of $\text{NaOH}$ will produce 1 mole of $\left[O {H}^{-}\right]$ in solution and 1 mole of ${\text{HNO}}_{3}$ will produce 1 mole of $\left[{H}^{+}\right]$ in solution.

The solution should produce a $\text{pH}$ of $7$ since equal amounts of the acid and base react and neither the acid or the base is in excess, therefore

$\textcolor{w h i t e}{a a a a a a a a a a a a a a a a} \left[O {H}^{-}\right] = \left[{H}_{3} \stackrel{\text{+}}{O}\right]$