Question #7c60d
1 Answer
Feb 24, 2018
Explanation:
#"using the formula for "color(blue)"arc length"#
#• " arc length "="circumference "xx" fraction of circle"#
#color(white)(xxxxxxxxxx)=cancel(2pir)xx(angleAOB)/(cancel(2pi))#
#color(white)(xxxxxxxxxx)=5xxangleAOB#
#rArr5angleAOB=10rArrangleAOB=10/5=2" radians"#