# What mass of carbon dioxide results from combustion of a 52*g mass of acetylene gas?

May 27, 2017

We needs a stoichiometric equation, and we finally get a mass of $C {O}_{2}$ under $200 \cdot g$.

#### Explanation:

And the typical rigmarole is to balance the carbons, and then the hydrogens, and then finally the oxygens.............

$H C \equiv C H \left(g\right) + \frac{5}{2} {O}_{2} \left(g\right) \rightarrow 2 C {O}_{2} \left(g\right) + {H}_{2} O \left(l\right)$

Is this balanced? Don't trust my 'rithmetic!

And thus, moles of acetylene reactant:

$= \frac{52 \cdot g}{26.04 \cdot g \cdot m o {l}^{-} 1} = 2 \cdot m o l$

Given the stoichiometry, we gets $4 \cdot m o l$ $C {O}_{2} \left(g\right)$ given complete combustion, a mass of $4 \cdot m o l \times 44.0 \cdot g \cdot m o {l}^{-} 1 = 176 \cdot g$ $\text{carbon dioxide..........}$ Take that atmosphere!

Would this reaction be exothermic? Why or why not?