# Question #3d50c

##### 1 Answer

Jun 1, 2017

+1

#### Explanation:

to calculate the oxidation no. of s let it be x

wkt oxd no of H= +1

oxd no of O= -2

no ion charge so total charge =0

then 2*(+1) + 2*x + 2*(-2) =0

=> +2 + 2x + (-4) =0

=> 2x -2 =0

=> 2x= 2

=> x=1 ( oxd no of s)

............................hope it helps........................:)