What mass of dihydrogen gas results from the oxidation of #20*g# sodium metal by a mass of #10*g# of water?
Well first we write a stoichiometric equation, and get a bit over
We represent the reaction by the following stoichiometric equation:
You can double this if you like. I think the arithmetic is easier if you include the
Now, here (UNUSUALLY) water is the reagent in DEFICIENCY. And thus we assume that only
And thus we get