Question

What molar quantity of `HCl` is present in a `23.6*cm^3` volume of `0.1*mol*L^-1` concentration?

Answer 1

You need to quote the `"density"`, `rho`, of the acid solution..........

Explanation:

As a matter of fact, the density of this (fairly dilute) acid would be very close to that of water, i.e. `rho=1*g*cm^-3`. However, we need it to get the volume of the acid............and THEN we can calculate the number of moles this mass of solution contains quite precisely.