Question #cb30d

Jun 2, 2017

165.6g

Explanation:

Number of moles of $N a N {O}_{3}$ in 85g = 85/85 = 1 mole

$P b O + 2 N a N {O}_{3} \rightarrow P b {\left(N {O}_{3}\right)}_{2} + N {a}_{2} O$

2 moles of $N a N {O}_{3}$ required to react with $P b O$ to form $P b {\left(N {O}_{3}\right)}_{2}$. Therefore, 0.5 moles of $P b {\left(N {O}_{3}\right)}_{2}$ are produced.
Molar mass of $P b {\left(N {O}_{3}\right)}_{2}$ = 331.2g
Therefore, mass of $P b {\left(N {O}_{3}\right)}_{2}$ produced = 331.2/2 = 165.6g