Question

How many different choices are there from: given 4 choose 3? The order does not patter.

Answer 1

4

Explanation:

The 2 conditions of, order matters and does not matter, have just one difference in the formula.

Order matters: `ab` is not the same as `ba:" "->"Permutation"`

Order does not matters: `ab` is the same as `ba:" "->"Combination"`

Permutation `->(n!)/((n-r)!)" written as "color(white)()^nP_r`

Combination `->(n!)/((n-r)!r!)" written as "color(white)()^nC_r`

Note that Permutation count > Combination count

This would be the case as the denominator of the combination formula has the `r!` in it whilst that of the permutation denominator does not.

We need `color(white)()^nC_r->(n!)/((n-r)!r!)" "->" "(4!)/((4-3)!3!)`

`=(4xx3xx2xx1)/(3xx2xx1) = 24/6=4`