What integer solutions are there to #1/(x+y)+1/(x-y) = 4/9# ?

1 Answer
Jul 20, 2017

Integer solutions are: #y=+-3# (with #x=6#) or #y=+-10# (with #x=-8#).

Explanation:

Suppose:

#1/m + 1/n = 4/9" "# for some integers #m, n#

Dealing first with the case #m, n > 0#:

Without loss of generality #m <= n# and we have:

#2/9 <= 1/m < 4/9#

Taking reciprocals and reversing the inequalities, that means:

#9/4 < m <= 9/2#

Hence #m = 3# or #m = 4#

If #m=3# then:

#1/n = 4/9 - 1/3 = 1/9" "# which works.

If #m=4# then:

#1/n = 4/9 - 1/4 = 7/36" "# which does not work.

So the only positive #m, n# with #1/m+1/n = 4/9# are #3, 9#

Hence we can put #x+y=9# and #x-y=3#, finding #x=6#, #y=3# and:

#1/(x+y)+1/(x-y) = 4/9#

Another solution is given by #x=6# and #y=-3#.

What about negative values of #n# ?

If #1/m > 4/9# then #m=1# or #m=2#

If #m=1# then #1/n = 4/9-1 = -5/9" "# which does not work.

If #m=2# then #1/n = 4/9 - 1/2 = -1/18" "# giving #n=-18#

Hence we can put #x = -8# and #y = +-10# to get two further integer solutions.