Question #98339

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Answer 1 · 2017-06-01T07:44:23

#n(O_2):n(SO_2) = 2:1#

Molar mass of #O_2#: #2*16=32# (g/mol)
Molar mass of #SO_2#: #1*32 # (one sulfur atom) #+ 2*16# (two oxygen atoms) #= 64# (g/mol)

Number of molecules in each gram of substance:
#O_2#: #1/32#
#SO_2#: #1/64#

#(n(O_2))/(n(SO_2)) = (1/32)/(1/64) = 2/1#

Answer 2 · 2017-06-01T07:45:09

2 : 1

Molar Mass of #O_2# = 32 #g mol^-1#
#rArr# 1 g of #O_2# = #1/32 mol#

And Molar Mass of #SO_2# = #32 + 2 * 16 g mol^-1 = 64 g mol^-1#
#rArr# 1 g of #SO_2# = #1/64 mol#

Hence, #O_2 : SO_2#
#rArr# #1/32 N_A : 1/64 N_A#
#rArr# #2 : 1#