# Question #98339

Jun 1, 2017

$n \left({O}_{2}\right) : n \left(S {O}_{2}\right) = 2 : 1$

#### Explanation:

Molar mass of ${O}_{2}$: $2 \cdot 16 = 32$ (g/mol)
Molar mass of $S {O}_{2}$: $1 \cdot 32$ (one sulfur atom) $+ 2 \cdot 16$ (two oxygen atoms) $= 64$ (g/mol)

Number of molecules in each gram of substance:
${O}_{2}$: $\frac{1}{32}$
$S {O}_{2}$: $\frac{1}{64}$

$\frac{n \left({O}_{2}\right)}{n \left(S {O}_{2}\right)} = \frac{\frac{1}{32}}{\frac{1}{64}} = \frac{2}{1}$

2 : 1

#### Explanation:

Molar Mass of ${O}_{2}$ = 32 $g m o {l}^{-} 1$
$\Rightarrow$ 1 g of ${O}_{2}$ = $\frac{1}{32} m o l$

And Molar Mass of $S {O}_{2}$ = $32 + 2 \cdot 16 g m o {l}^{-} 1 = 64 g m o {l}^{-} 1$
$\Rightarrow$ 1 g of $S {O}_{2}$ = $\frac{1}{64} m o l$

Hence, ${O}_{2} : S {O}_{2}$
$\Rightarrow$ $\frac{1}{32} {N}_{A} : \frac{1}{64} {N}_{A}$
$\Rightarrow$ $2 : 1$