Question #9e796

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Answer 1 · 2017-06-03T08:19:26

#z=-0.5#

for#" "Z~N(1,0)#

we want #P(Z>z)=0.6915#

(i) the tables only give #P(Z < z)#

(i) also we need to know #P(Z<0)=0.5#which means that the #z# value we want will be a negative value

we use

#P(Z < z)=0.6915=>z=0.5" "#from tables

since #z<0#

we conclude that

#z=-0.5#