# A gas occupies "0.5650 L" in a closed container. The initial pressure is "______" if the volume increases to "1.204 L" at a pressure of "715.1 bar"?

Jun 2, 2017

The initial pressure, which goes in the blank, was $\text{1524 bar}$.

#### Explanation:

This question involves Boyle's gas law , which states that the volume of a given amount of a gas varies inversely with the pressure, as long as temperature is kept constant. This means that when the volume increases, the pressure decreases, and vice-versa. The equation you will need to answer this question is:

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

In your question, the blank is the initial pressure, ${P}_{1}$, whis is your unknown. Organize the rest of the data.

Known

${V}_{1} = \text{0.5650 L}$

${P}_{2} = \text{715.1 bar}$

${V}_{2} = \text{1.204 L}$

Solution

Rearrange the equation above to isolate ${P}_{1}$. Insert the known data into the equation and solve.

${P}_{1} = \frac{{P}_{2} {V}_{2}}{{V}_{1}}$

P_1=(715.1"bar"xx1.204color(red)cancel(color(black)("L")))/(0.5650color(red)cancel(color(black)("L")))="1524 bar" (rounded to four sig figs)