Question #a4cd9

1 Answer
Jun 3, 2017

Answer:

No ppt forms ... #K_"sp" (=2.4 x 10^-5)# > #Q_"sp"(1.6x10^-5)#

Explanation:

#20ml(0.01MCaCl_2) + 20ml(0.008MNa_2SO_4)#
=> #(0.02)(0.01)"mole" CaCl_2# + #(0.02)(0.008)"mole" Na_2SO_4#
=> #0.0002"mole" CaCl_2# + #0.00016"mole"Na_2SO_4#

=> #Na_2SO_4# is the limiting reagent => #1.6x10^-4"# mole #CaSO_4#

#[CaSO_4]# = #1.6x10^-4"# #"mole" CaSO_4# / #"0.040L Solution"# = #0.004M#

0.004M#CaSO_4 rightleftharpoons# +0.004M#(Ca^(+2))# + 0.004M#(SO_4^(2-))#

#Q_(sp) = [Ca^(+3)][SO_4^(2-)] = (0.004M)(0.004M)# = #1.6x10^-5#

#K_(sp)=2.4x10^-5 > Q_(sp) = 1.6x10^-5# => No Ppt will form.