Question

Prove that `(1/log_xa)+(1/log_xb)=log_ax+log_bx`?

Answer 1

`(1/log_xa)+(1/log_xb)=log_ax+log_bx`

Explanation:

Let `log_am=p`, this means that `a^p=m`

this isequivalent to `m^(1/p)=a` i.e. `log_ma=1/p`

Hence `(1/log_xa)+(1/log_xb)`

= `log_ax+log_bx`