# Question #7e5b1

##### 1 Answer

Here's how I would do it.

#### Explanation:

**(a)** Radius of sphere

You get the radius of the sphere from the volume of the displaced water.

The formula for the volume

#color(blue)(bar(ul(|color(white)(a/a) V = 4/3πr^3color(white)(a/a)|)))" "#

where

We can rearrange this formula to get

∴

**(b)** Density of metal block

You get the density

#color(blue)(bar(ul(|color(white)(a/a)ρ = m/Vcolor(white)(a/a)|)))" "#

Assume that

**(c)** Density of wood

You apparently removed the metal sphere for this experiment.

The original volume was

The metal block had a volume of

When you submerged the wooden block,

∴The volume of the wooden block is

Assume that the mass of the wood is 7.5 g. Then