# Question 60dd4

$132$ $\text{mm Hg}$
We can take note of the fact that air is roughly 21% oxygen. The mole fraction of oxygen in air is thus $0.21$, and using this, the partial pressure is
P_("O"_2) = (0.21)(630"mm Hg") = color(red)(132 color(red)("mm Hg"#