# What mass of zinc metal will be oxidized if 15.0*g of FeI_3 react to give iron metal?

Jun 5, 2017

Approx. $4 \cdot g$ zinc will be oxidized

#### Explanation:

Zinc is higher on the activity series than iron; it should therefore reduce the iron salt:

i.e. $\stackrel{0}{Z} n \left(s\right) \rightarrow Z {n}^{2 +} + 2 {e}^{-}$ $\left(i\right)$

And for every oxidation there is a corresponding reduction..........

i.e. $F {e}^{3 +} + 3 {e}^{-} \rightarrow \stackrel{0}{F} e \left(s\right)$ $\left(i i\right)$

We cross multiply: $2 \times \left(i i\right) + 3 \times \left(i\right) :$

$3 Z n \left(s\right) + 2 F {e}^{3 +} \rightarrow 3 Z {n}^{2 +} + 2 F e \left(s\right)$

Both mass and charge are conserved, so this is a valid representation..........

We has $\frac{15.0 \cdot g}{399.88 \cdot g \cdot m o {l}^{-} 1} = 0.0375 \cdot m o l$ ferric salt.........and given the stoichiometry this will oxidize..........

3/2xx0.0375*molxx65.39*g*mol^-1=??*g zinc metal.......