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Answer 1 · 2017-06-05T13:41:51

#164.086g//mol#

#Ca(NO_3)_2=>Ca_color(red)1(N_color(blue)1O_color(green)3)_color(brown)2#

There are #(color(red)1Ca)#, #(color(brown)2xxcolor(blue)1N)#, #(color(brown)2xxcolor(green)3O)=>1Ca#, #2N#, #6O#

Find molar mass of each (coefficient#xx# atomic mass)

1) #1Ca#: #1xx40.078=40.078g//mol#

2) #2N#: #2xx14.007=28.014g//mol#

3) #6O#: #6xx15.999=95.994g//mol#

Add all these masses to get the molar mass of #Ca(NO_3)_2#

#40.078+28.014+95.994=164.086g//mol#