Question #b20ce

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Question #b20ce

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Answer 1 · 2017-06-06T01:15:39

$(0, 6)$ $(0,6)$

Explanation:

Firstly, what you have written is an equation not a function. The function is $y = 3 x^{2} - 12 x + 6$ $y=3x^2-12x+6$ .

$y$ $y$ -intercept occurs when $x$ $x$ is 0
$y = 3 x^{2} - 12 x + 6$ $y=3x^2-12x+6$
Substituting $x = 0$ $x=0$ into above,
$y = 3 \cdot 0^{2} - 12 \cdot 0 + 6$ $y=3*0^2-12*0+6$
$y = 6$ $y=6$
Therefore, $y$ $y$ -intercept is $(0, 6)$ $(0,6)$ .

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Question #b20ce

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