# Question #fa525

Jun 6, 2017

$\text{Molarity"="Moles of solute"/"Volume of solution}$
And thus molarity has units of $m o l \cdot {L}^{-} 1$.
On t'other hand, $\text{Molality"="Moles of solute"/"Kilograms of solvent}$, and thus has units of $m o l \cdot k {g}^{-} 1$.