# Which option contains a 2*g mass of sodium atoms.... 1. 5.24xx10^22*"sodium atoms?" 2. 6.022xx10^24*"sodium atoms?" 3. 3.12xx10^23*"sodium atoms?" 4. 5.24xx10^22*"sodium atoms?"

Jun 8, 2017

I would say $\text{option 1........}$

#### Explanation:

We know that $1 \cdot m o l$ contains $6.022 \times {10}^{23}$ individual sodium atoms, and has a mass of $22.99 \cdot g$.

And thus for $1.$ there is a $2 \cdot g$ mass of $N a$.

For $2.$ there is a $22.99 \cdot g$ mass of $N a$.

For $3.$ there is a ..............................

$\left(3 \times {10}^{23} \cdot \text{sodium atoms")/(6.022xx10^23*"sodium atoms} \cdot m o {l}^{-} 1\right) \times 22.99 \cdot g \cdot m o {l}^{-} 1$ mass of $N a$, approx. $11.5 \cdot g$.

For $4.$ there is a $8 \cdot g$ mass of sodium............

And so, clearly,..................Capisce?