# Question #a48f7

Jun 14, 2017

Propane molecular weight is 44 g/mol. Your answer is 150 grams of $C {O}_{2}$

#### Explanation:

Find the mol of propane that is combusted:

$\frac{50}{44}$

$= 1.136$ mol

It means you spent 1.136 mol of propane, to get $3 \times 1.136$ moles of carbondioxide. That is $3.41$ moles of carbondioxide.

Since $C {O}_{2}$ has a molecular weight of 44 grams per mol,

it means you get $44 \times 3.41$

$= 150$ grams of carbondioxide you get after full combustion of propane.