# What is the molar quantity of NO(g) that expresses a volume of 4.34*L under standard conditions?

Jun 15, 2017

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#### Explanation:

We know that an Ideal Gas has expresses a molar volume of $22.4 \cdot L$ at $\text{STP}$.

And thus $\text{moles of nitric oxide}$ $=$ $\frac{4.34 \cdot \cancel{L}}{22.4 \cdot \cancel{L} \cdot m o {l}^{-} 1}$

$= 0.194 \cdot m o l$, i.e. $\frac{1}{m o {l}^{-} 1} = \frac{1}{\frac{1}{m o l}} \equiv m o l \ldots \ldots \ldots \ldots .$

And is $\text{nitric oxide}$ an Ideal Gas? Well, no, but under these conditions, nitric oxide would approximate Ideal Gas behaviour.