# Question #58587

##### 1 Answer

#### Answer:

#### Explanation:

This is essentially a problem involving dilution, but without the volumes or molarities. *The moles (and thus grams) of the solute* (*before and after the dilution must be the same*.

We can therefore set up this question by asking,

"

The number of grams present is

So therefore,

One way we can check this answer is by seeing if, in both cases, the percentage multiplied by the total solution mass is the same number,