# Question 7b280

Jun 17, 2017

130 ml of stock concentrate $H N {O}_{3}$ plus solvent up to but not to exceed 750 ml total solution volume.
("Molarity"xx"Volume")_"concentrate"=("Molarity"xx"Volume")^"diluted"#
$\left(5.75 M\right) \left({V}_{c}\right)$ = $\left(0.750 L\right) \left(1.00 M\right)$
${V}_{c} = \frac{\text{(0.750L)(1.00M)}}{5.75 M} = 0.130 L = 130 m l$
Mixing => Transfer 130 ml of the 5.75M $H N {O}_{3} \left(a q\right)$ solution into mixing container & add solvent up to but not to exceed 750 ml. total volume.