Find the value of #sqrt(7^log5)-sqrt(5^log7)#?

1 Answer
Shwetank Mauria
Dec 2, 2017

#sqrt(7^log5)-sqrt(5^log7)=0#

Explanation:

Let #sqrt(7^log5)=u#, then #logu=log(sqrt(7^log5))#

= #1/2log5xxlog7#

Similarly #sqrt(5^log7)=v#, then #logv=log(sqrt(5^log7))#

= #1/2log7xxlog5#

and therefore #logu=logv# i.e. #u=v#

Hence #sqrt(7^log5)-sqrt(5^log7)=0#

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