How do you solve #2/3x=3/8x+7/12#?

1 Answer
Jun 20, 2017

#x=2#

Explanation:

Solve:

#2/3x=3/8x+7/12#

Simplify #2/3x to (2x)/3#, and #3/8x to (3x)/8#.

#(2x)/3=(3x)/8+7/12#

Determine the least common denominator (LCD).

#3:##3,6,9,12,15,18,21,color(red)24,27...#
#8:##8,16,color(red)24...#
#12:##12,color(red)24...#

The LCD is #24#.

Multiply both sides by #24#.

#24xx(2x)/3=(24xx(3x)/8)+(24xx7/12)#

Simplify.

#color(red)cancel(color(black)(24^8))xx(2x)/color(red)cancel(color(black)(3^1))=(color(red)cancel(color(black)(24^3))xx(3x)/color(red)cancel(color(black)(8^1)))+(color(red)cancel(color(black)(24^2))xx7/color(red)cancel(color(black)(12^1)))#

#16x=9x+14#

Subtract #9x# from both sides.

#16x-9x=14#

Simplify.

#7x=14#

Divide both sides by #7#.

#x=14/7#

Simplify.

#x=2#