Question #9b514

1 Answer
Jun 23, 2017

See below.

Explanation:

Hardy Weinberg principle states that allele frequencies in a population are stable and is consistent from generation to generation.

Sum total of all the allelic frequencies is 1. In a diploid cell, #p# and #q# represent the frequency of allele A and a.

The frequency of AA individuals is simply #p^2#.

Similarly of aa is #q^2#, of Aa is #2pq#.

Hence #p^2 + q^2 + 2pq = 1#.


1] Allele frequency of R is 20%.
Which means #p = (20/100) = 0.2#

Now, #p + q = 1#
#q = 0.8#

The frequency of RR, i.e #p^2 = (0.2)^2 = 0.04#.

The frequency of rr, i.e #q^2 = (0.8)^2 = 0.64#.

The frequency of Rr, i.e #2pq = (2)(0.2)(0.8) = 0.32#

2] Total number of individuals #= 400#
Number of homozygous recessive individuals #= 9#

Frequency of homozygous individuals i.e, #q^2 = (9/400) = 0.0225#.

Frequency of the allele #q = sqrt(0.0225) = 0.15#

Frequency of #p = 1 - q = 0.85#


I answered two of them. Try the others as I've told you the concept. If you get stuck on any of them let me know.