# Question 09add

Jun 23, 2017

$X = 32.1 \frac{g}{m}$

#### Explanation:

Set up a ratio and solve for X

 5.72 /10 = (4x)/ ( 4x + 6(O)#

5.72 = the amount of X in the compound

4x = the amount of X in the compound

so $5.72 = 4 x$

10 = the total amount of the Compound

4x + 6(O) the total amount of the Compound

so $10 = 4 X + 6 \left(O\right)$ The ratio is

$\frac{5.72}{10} = \frac{4 X}{4 X + 6 O}$

$6 \times 16 = 96$ : $O = 16 \frac{g}{m}$

$\frac{5.72}{10} = \frac{4 x}{4 X + 96}$ removing the denominators gives

$5.72 \left(4 x\right) + 5.72 \left(96\right) = 40 X$ multiplying this out gives.

$22.88 X + 549. = 40 X$ subtract 22.88 X from both sides

$22.88 X - 22.88 X + 549 = 40 X - 22.88 X$ This gives

$549 = 17.12 X$ divide both sides by 17.12 gives

$32.1 g . = X$

Within the margin of error the grams / mole is approximately 32 grams/mole X is probably Sulfur