# Given EXCESS zinc metal, what volume of dihydrogen gas at "NTP" will be evolved from the action of 500*cm^3 of H_2SO_4 at 0.50*mol*L^-1 concentration?

Jun 24, 2017

We interrogate the redox reaction......

$Z n \left(s\right) + {H}_{2} S {O}_{4} \left(a q\right) \rightarrow Z n S {O}_{4} \left(a q\right) + {H}_{2} \left(g\right) \uparrow$

#### Explanation:

And thus ONE equiv of dihydrogen results from each equiv of sulfuric acid (and also from each equiv of zinc metal).........

As far as I know $\text{NTP}$ specifies $1 \cdot a t m$ pressure and $293.15 \cdot K$, and the molar volume of an Ideal Gas at $N T P$ is $24.05 \cdot L$

$\text{Moles of sulfuric acid} = 500 \cdot c {m}^{3} \times {10}^{-} 3 \cdot L \cdot c {m}^{-} 3 \times 0.5 \cdot m o l \cdot {L}^{-} 1 = 0.25 \cdot m o l$

And thus $0.25 \cdot m o l$ dihydrogen gas will be evolved.

And so volume at $\text{NTP} = 0.25 \cdot m o l \times 24.05 \cdot L \cdot m o {l}^{-} 1 \cong 6 \cdot L$