A #3.49*g# mass of a gas occupies a volume of #4.48*dm^3# under standard conditions, what is the molar mass of the gas?

1 Answer
Jun 26, 2017

Answer:

#"Molar mass"=17.5*g*mol^-1#

Explanation:

Depending on your syllabus, at #"STP"# #1*mol# of Ideal Gas occupies #22.4*dm^3#, i.e. #22.4*dm^3*mol^-1#.......and note that #1*dm^3=1xx(10^-1*m)^3=1/1000*m^3=1*L#, cos' there are #1000*L# in a #"cubic metre"#.

And thus the #"molar mass"="mass"/"molar quantity"#

#=(3.49*g)/((4.48*dm^3)/(22.4*dm^3*mol^-1))=17.5*g*mol^-1#.......