Question #9caae
1 Answer
Answer:
Explanation:
We're asked to find the equilibrium constant
The equilibrium constant expression for this reaction is
If
We can tabulate now our initial concentrations for each species:
Initial:

#"SO"_3# :#0.187M# 
#"SO"_2# :#0# 
#"O"_2# :#0#
The changes in concentration, which we'll call the variable
Change:

#"SO"_3# :#2x# (coefficient of 2) 
#"SO"_2# :#+2x# (coefficient of 2) 
#"O"_2# :#+x# (coefficient of 1)
We know the final equilibrium concentration of
Therefore, the variable
Using this value, we can now find the equilibrium concentrations of all species:
Equilibrium:

#"SO"_3# :#0.187M  2(0.0289M) = 0.129M# 
#"SO"_2# :#0 + 2(0.0289M) = 0.0578M# 
#"O"_2# :#0 + 0.0289M = 0.0289M#
And lastly, we can plug in these values to the equilibrium constant expression to calculate