What are the oxidation states of the elements, and how are these assigned in compounds?

1 Answer
Jun 27, 2017

Answer:

Oxidation states for the elements?

Explanation:

The oxidation state of a neutral element is ZERO............

#1.# #"The oxidation number of a free element is always 0."#

#2.# #"The oxidation number of a mono-atomic ion is equal"# #"to the charge of the ion."#

#3.# #"For a given bond, X-Y, the bond is split to give "X^+# #"and"# #Y^-#, #"where Y is more electronegative than X."#

#4.# #"The oxidation number of H is +1, but it is -1 in when"# #"combined with less electronegative elements."#

#5.# #"The oxidation number of O in its"# compounds #"is usually -2, but it is -1 in peroxides."#

#6.# #"The oxidation number of a Group 1 element"# #"in a compound is +1."#

#7.# #"The oxidation number of a Group 2 element in"# #"a compound is +2."#

#8.# #"The oxidation number of a Group 17 element in a binary compound is -1."#

#9.# #"The sum of the oxidation numbers of all of the atoms"# #"in a neutral compound is 0."#

#10.# #"The sum of the oxidation numbers in a polyatomic ion"# #"is equal to the charge of the ion."#

For a simple oxidation reaction, the combustion of coal, we can write the following redox reaction,,,,,,,

#stackrel(0)C(s)+stackrel(0)O_2(g)rarrstackrel(-II)O=stackrel(+IV)C=stackrel(-II)O(g)#

For the elements in their compounds, the maximum oxidation state expressed is the Group Number of that element........