# What is the molar concentration of a 2%("weight"/"volume") solution of sodium hydroxide?

Jun 29, 2017

We assume that we deal with a 2% $\text{weight"/"volume}$ solution......

#### Explanation:

That is $2 \cdot g$ of $\text{sodium hydroxide}$ are dissolved in a $100 \cdot m L$ volume of water........

$\text{Concentration"="Moles of solute"/"Volume of solution}$

$= \frac{\frac{2.0 \cdot g}{39.99 \cdot g \cdot m o {l}^{-} 1}}{100 \cdot m L \times {10}^{-} 3 \cdot L \cdot m {L}^{-} 1} = 0.500 \cdot m o l \cdot {L}^{-} 1$

Please note my assumption.......in questions of this kind normally the density of the solution would also be quoted.