Is #n!# differentiable?

1 Answer
Jun 30, 2017

See explanation below.

Explanation:

Since #n!# is a discrete function, only defined for #n>=0 , n inZZ# it is not differentiable as it stands.

However, there is an extension of #n!# into the real numbers;

#f(x) = Gamma(x+1): x in RR# which is continuous and differentiable for #x>=1# and equivalent to #n!# for #x=n in NN#.

See also: http://www.intmath.com/blog/mathematics/factorials-and-the-gamma-function-4350

Hope this makes sense.