Given the ammonia synthesis: #N_2(g) + 3H_2(g) rarr 2NH_3(g)# #DeltaH_"rxn"^@=-92.6*kJ*mol^-1#, what reaction enthalpy is associated with the formation of #8.55xx10^4*g# of ammonia?
How? We use the enthalpy as a variable in the reaction..........and get
Which tells that the formation of
But here we have made much more than 2 mol ammonia, and the enthalpy changes appropriately.