Potassium iodide is added to a solution of lead nitrate....what are...?

#"A. The solid product of reaction?"#
#"B. The colour of this product?"#
#"C. A stoichiometric equation to represent the reaction?"#
#"D. Can the reaction be described as a solubility equilibrium?"#

1 Answer
Jul 1, 2017

Answer:

I presume you mean potassium iodide, #KI#.....is added to the aqueous lead salt.

Explanation:

#A.# #"Lead iodide"#

#B.# #"Lead iodide"# gives a beautiful, bright yellow precipitate......

#C.# #Pb(NO_3)_2(aq) + 2KI(aq) rarr PbI_2(s)darr+ 2KNO_3(aq)#

The net ionic equation is........

#Pb^(2+) + 2I^(-) rarr PbI_2(s)darr#

#D.# This is a #"solubility equilibrium"#, where the salt #PbI_2# is highly insoluble. I suppose you could also call it a #"metathesis"# or #"partner exchange"# reaction........but I do not know what your syllabus specifies.....Experimentally, we KNOW that all halides are soluble, EXCEPT for those of #Hg_2^(2+)#, #Pb^(2+)#, and #Ag^+#. In the 1st year curriculum, this must simply be known.

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