Question #46d57

1 Answer
Jul 4, 2017

Answer:

The formality is 0.0200 mol/L.

Explanation:

The formality #F# of a solution is the number of moles #n# of the ionic solute dissolved in one litre of the solution.

#color(blue)(bar(ul(|color(white)(a/a)F = "moles"/"litres" = n/Vcolor(white)(a/a)|)))" "#

#n = 2.02 color(red)(cancel(color(black)("g KNO"_3))) × ("1 mol KNO"_3)/(101.10 color(red)(cancel(color(black)("g KNO"_3)))) = "0.020 00 mol KNO"_3#

#V = "1 L"#

#F = "0.020 00 mol"/"1 L" = "0.0200 mol/L"#