Question #c2449
1 Answer
Jul 4, 2017
#Ag^+# +#e^-# =>#Ag^o#
#Br^-# =>#1/2"Br_2# +#e^-#
#Ni^(+2)# +#2e^-# =>#Ni^o#
#2Cl^-# =>#Cl_2# +#2e^-#
#Fe^(+2)# +#2e^-# =>#Fe^o#
#2Cl^-# =>#Cl_2# +#2e^-#