# How does sulfur oxidize aluminum?

Jul 6, 2017

$2 A l \left(s\right) + 3 S \left(s\right) \stackrel{\Delta}{\rightarrow} A {l}_{2} {S}_{3} \left(s\right)$

#### Explanation:

Sometimes you will see elemental sulfur formulated as ${S}_{8}$, in which case we would write......

$2 A l \left(s\right) + \frac{3}{8} {S}_{8} \left(s\right) \stackrel{\Delta}{\rightarrow} A {l}_{2} {S}_{3} \left(s\right)$.......

So 2 questions..........

$\text{(i) Is this an oxidation reduction reaction?}$

$\text{(ii) This material is highly non-molecular. What does this mean?}$