How do I represent #"2,3-dimethylpentanaldehyde"#?

1 Answer
anor277
Jul 7, 2017

Well what have you got so far?

Explanation:

Let's take #(b)#. Step one is to identify the longest chain, which here is a 5-carbon chain, capped by a #C=O(H)#, and thus we have a #"pentaldehyde derivative"#.......

#H_3stackrel(5)Cstackrel(4)CH_2stackrel(3)CH(CH_3)stackrel(2)CH(CH_3)stackrel(1)C(=O)H#

#stackrel(2)C# and #stackrel(3)C# are substituted by methyl groups. Are these centres chiral?

And so we have.....#"2,3-dimethylpentanaldehyde"#.......

Anyway, you will have to attempt the other structures yourself.

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