# Question #19e8d

Jul 8, 2017

Given that an empty relative density bottle has a mass of 15g.when completely filled with water its mass is 39g..

So the mass of water filling the bottle completely is $\left(39 - 15\right) = 24 g$

So the inner volume of the bottle or the volume of this water will be $= \text{mass of water"/"density of water}$

$= \frac{24 g}{1 \frac{g}{m L}} = 24 m L$

when the bottle is completely filled with acid of relative density 1.2, the mass of acid in it is $= 24 m L \times 1.2 \frac{g}{m L} = 28.8 g$

So mass of the bottle completely filled with acid will be

$= \text{mass of empty bottle" +" mass of acid filling it}$

$= 15 + 28.8 = 43.8 g$