Question

Question #b3d2c

Answer 1

If Question is

`sin2x=sin60cos30-cos60-sin30`

`=>sin2x=sqrt3/2xxsqrt3/2-1/2-1/2`

`=>sin2x=3/4-1=-1/4`

`=>2x=sin^-1(-1/4)`

`=>2x=-14.48^@`

`=>x=-14.48^@/2=-7.24^@`

Answer 2

`x = - 7^@24 + k180^@`
`x = 97^@24 + k180^@`

Explanation:

`sin 2x = 3/4 - 1/2 - 1/2 = - 1/4`
`sin 2x = - 1/4 = - 0.25`
Calculator and unit circle give 2 solutions;
a. `2x = - 14^@48 + k360^@` --> `x = - 7^@ 24 + k180^@`
b. `2x = 180 - (-14.48) = 194^@48 + k360^@` -->
`x = 97^@24 + k180^@`