Question

What is the molar quantity contained in a `0.280*L` volume of `N_2O`?

Answer 1

Well, first you have to specify a temperature and pressure......

Explanation:

And typically, we specify a temperature of `298*K`, and a pressure of `1*atm`. There are all sorts of these standards depending on the syllabus, and how childish your prof is......

The one I will use here is that an ideal gas occupies `25.4*L` under these conditions........

And thus `"moles of nitrous oxide"=(0.280*L)/(25.4*L*mol^-1)` `=` `0.0110*mol.........`

Of course we know that `1000*cm^3-=1.000*L`.....