# What is the molar quantity contained in a 0.280*L volume of N_2O?

Jul 12, 2017

Well, first you have to specify a temperature and pressure......

#### Explanation:

And typically, we specify a temperature of $298 \cdot K$, and a pressure of $1 \cdot a t m$. There are all sorts of these standards depending on the syllabus, and how childish your prof is......

The one I will use here is that an ideal gas occupies $25.4 \cdot L$ under these conditions........

And thus $\text{moles of nitrous oxide} = \frac{0.280 \cdot L}{25.4 \cdot L \cdot m o {l}^{-} 1}$ $=$ $0.0110 \cdot m o l \ldots \ldots \ldots$

Of course we know that $1000 \cdot c {m}^{3} \equiv 1.000 \cdot L$.....