Question #0322c
1 Answer
Here's what I got.
Explanation:
The trick here is that the iron(III) cations will combine with the thiocyanate anions to form the thiocyanatoiron(III) complex ion,
Now, you could say that the balanced chemical equation that describes this reaction looks like this
#"Fe"("NO"_ 3)_ (3(aq)) + 3"KSCN"_ ((aq)) -> "Fe"("SCN")_ (3(aq)) + 3"KNO"_ (3(aq))#
However, that would not be an accurate depiction of what happens in solution because
If you keep in mind the fact that the reaction produces the thiocyanatoiron(III) complex ion, you can say that the complete ionic equation that describes this reaction looks like this
#"Fe"_ ((aq))^(3+) + color(red)(cancel(color(black)(3"NO"_ (3(aq))^(-)))) + color(red)(cancel(color(black)(3"K"_ ((aq))^(+)))) + overbrace("SCN"_ ((aq))^(-) + color(red)(cancel(color(black)(2"SNC"_ ((aq))^(-)))))^(color(blue)("= 3SCN"_ ((aq))^(-)))-> "Fe"("SCN")_ ((aq))^(2+) + color(red)(cancel(color(black)(2"SNC"_ ((aq))^(-)))) + color(red)(cancel(color(black)(3"K"_ ((aq))^(+)))) + color(red)(cancel(color(black)(3"NO"_ (3(aq))^(-))))#
The nitrate anions, the potassium cations, and
#"Fe"_ ((aq))^(3+) + "SCN"_ ((aq))^(-) -> "Fe"("SCN")_ ((aq))^(2+)#
Now, you can write an even more accurate depiction of what happens in solution by taking into account the fact that iron(III) cations exist as hexaaquairon(III) complex ions in aqueous solution.
#"Fe"_ ((aq))^(3+) + 6"H"_ 2"O"_ ((l)) rightleftharpoons "Fe"("H"_ 2"O")_ (6(aq))^(3+)#
The reaction between the hexaaquairon(III) complex ion,
So the net ionic equation that describes this reaction can be written like this
#"Fe"("H"_ 2"O")_ (6(aq))^(3+) + "SCN"_ ((aq))^(-) rightleftharpoons ["Fe"("H"_ 2"O")_ 5("SCN")]_ ((aq))^(2+)#
This reaction is used a test for iron(III) cations because the addition of the clear solution of thiocyanate anions to a yellowish solution that contains the iron(III) cations as the hexaaquairon(III) complex ions will change the color of the solution to blood red.