A gas occupies #"1.46 L"# at a pressure of #"1.00 bar"#. What is the volume when the gas is dropped into the ocean to a depth such that the pressure is increased to #"60.0 bar"#?

1 Answer
Jul 20, 2017

Answer:

The final volume #(V_2)# is #"0.0243 L"#.

Refer to the explanation for the process.

Explanation:

This question involves Boyle's law, which states that the volume of a gas held at constant temperature varies inversely with the pressure. The means that if the volume increases, the pressure decreases, and vice versa. The equation for Boyle's law is:

#P_1V_1=P_2V_2#

Organize the data.

#P_1="1.00 bar"#

#V_1="1.46 L"#

#P_2="60.0 bar"#

#V_2="?"#

Solution

Rearrange the equation to isolate #V_2#. Substitute the data into the equation and solve.

#V_2=(P_1V_1)/P_2#

#V_2=(1.00color(red)cancel(color(black)("bar"))xx1.46"L")/(60.0color(red)cancel(color(black)("bar")))="0.0243 L"# (rounded to three significant figures)